5(x^2-2)=x(1-x)+10x)

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Solution for 5(x^2-2)=x(1-x)+10x) equation: 



5(x^2-2)=x(1-x)+10x)

We move all terms to the left:

5(x^2-2)-(x(1-x)+10x))=0

We add all the numbers together, and all the variables

5(x^2-2)-(x(-1x+1)+10x))=0

We multiply parentheses

5x^2-(x(-1x+1)+10x))-10=0

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